The specific conductivity of `N//50` KCl solution at 298 K is `2.768xx10^(-3)`mho per cm. The resistance of this solutions at 298 K when measured in a particular cell is 250.2 ohm. The resistance of `M//100 CuSO_(4)` solution at 298 K measured with the same cell was 8331 ohm. Calculate the molar conductivity of copper sulphate solution.

The specific conductivity of `N//50` KCl solution at 298 K is `2.768xx

1.	The specific conductivity of `N//50` KCl solution at 298 K is `2.768xx10^(-3)`mho per cm. The resistance of this solutions at 298 K when measured in a particular cell is 250.2 ohm. The resistance of `M//100 CuSO_(4)` solution at 298 K measured with the same cell was 8331 ohm. Calculate the molar conductivity of copper sulphate solution.
Answer» Correct Answer - `8.31 S cm^(2)mol^(-1)` Step I. Calculation of cell constant `R=250.2" ohm", k=2.768xx10^(-3)ohm^(-1) cm^(-1)` Cell constant `(l//a)=kxxR=(2.768xx10^(-3)ohm^(-1)cm^(-1))xx(250.2" ohm")=0.6925 cm^(-1)`. Step II. Calculation of molar conductane`(Lambda_(m))=(kxx1000)/(M)` Specific conductance (k)`=("cell constant")/(R )=((0.6925 cm^(-1)))/((8331" ohm"))=8.31xx10^(-6) ohm^(-1)cm^(-1)` Molarity of solution (M)=0.01 M `:. "Molar conductance" (Lambda_(m))=((8.31xx10^(-5)ohm^(-1) cm^(-1))xx(1000" cm"^(3)))/((0.01" mol"))` `= 831xx10^(-2)ohm^(-1) cm^(2) mol^(-1)=8.31" S " cm^(2) mol^(-1)`.

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