1.

The specific conductance of a solution is 0.2 ohm^(-1)" "cm^(-1) and conductivity is 0.04 ohm^(-1). The cell constant would be

Answer»

1 `cm^(-1)`
0 `cm^(-1)`
5 `cm^(-1)`
0.2 `cm^(-1)`

Solution :`K=Cxx`CELL CONSTANT`=(K)/(C)=(0.2)/(0.04)=5cm^(-1)`.


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