1.

The solution of the differential equation `ydx+ (x +x^2 y) dy =0` isA. `logy=Cx`B. `-(1)/(xy)+logy=C`C. `(1)/(xy)+logy=C`D. `-(1)/(xy)=C`

Answer» Correct Answer - B::D
We have,
`ydx+(x+x^(2)y)dy=0`
`rArr" "ydx+xdy+x^(2)ydy=0`
`rArr" "(d(xy))/((xy)^(2))+(1)/(y)dy=0" "["Dividing throughout by "(xy)^(2)]`
On integrating, we get `-(1)/(xy)+logy=C`


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