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The solution of primitive equation −ydydx=x√1−y2 is y=y(x), where y(x) is non-constant. If y(0)=1, then which of the following is/are correct |
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Answer» The solution of primitive equation −ydydx=x√1−y2 is y=y(x), where y(x) is non-constant. If y(0)=1, then which of the following is/are correct |
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