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The solution of 3(x^2-14)=(x+1)^2+(x-2)^2+(x-5)^2 is |
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Answer» Anwer: 3(x 2 −14)=(x+1) 2 +(x−2 ) 2+(x−5) 2
Use the distributive property to multiply 3 by x 2 −14.3x 2 −42=(x+1) 2+x−2 1 ) 2 +(x−5) 2
Use binomial THEOREM (a+b) 2 =a 2 +2ab+b 2 to expand (x+1) 2 . 3x 2 −42=x 2 +2x+1+(x−2 1 ) 2 +(x−5) 2
Calculate 2 to the power of 1 and get 2. 3x 2 −42=x 2 +2x+1+(x−2) 2 +(x−5) 2
Use binomial theorem (a−b) 2 =a 2 −2ab+b 2 to expand (x−2) 2 . 3x 2 −42=x 2 +2x+1+x 2 −4x+4+(x−5) 2
Combine x 2 and x 2 to get 2x 2 . 3x 2 −42=2x 2 +2x+1−4x+4+(x−5) 2
Combine 2x and −4x to get −2x. 3x 2 −42=2x 2 −2x+1+4+(x−5) 2
Add 1 and 4 to get 5. 3x 2 −42=2x 2 −2x+5+(x−5) 2
Use binomial theorem (a−b) 2 =a 2 −2ab+b 2 to expand (x−5) 2 . 3x 2 −42=2x 2 −2x+5+x 2 −10x+25 Combine 2x 2 and x 2 to get 3x 2 . 3x 2 −42=3x 2 −2x+5−10x+25 Combine −2x and −10x to get −12x. 3x 2 −42=3x 2 −12x+5+25 Add 5 and 25 to get 30. 3x 2 −42=3x 2 −12x+30 Subtract 3x 2 from both sides. 3x 2 −42−3x 2 =−12x+30 Combine 3x 2 and −3x 2 to get 0. −42=−12x+30 Swap sides so that all variable terms are on the LEFT hand side. −12x+30=−42 Subtract 30 from both sides. −12x=−42−30 Subtract 30 from −42 to get −72. −12x=−72 DIVIDE both sides by −12. x= −12 −72
Divide −72 by −12 to get 6. x=6 Step-by-step explanation: |
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