1.

The solution for the equations c1x+b1y+a1=0 and c2x+b2y+a2=0 is S1 : x=(b1a2–b2a1)(c1b2−c2b1) S2 : y=(a2c1–a1c2)(c2b1−c1b2)

Answer»

The solution for the equations c1x+b1y+a1=0 and c2x+b2y+a2=0 is

S1 : x=(b1a2b2a1)(c1b2c2b1)

S2 : y=(a2c1a1c2)(c2b1c1b2)




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