1.

The solublity of AgCl is formed when equal volumes of the following are mixed. [K_(sp) for AgCl = 10^(-10)]

Answer»

`2.0 xx 10^(-5) M`
`1.0 xx 10^(-4) M`
`5.0 xx 10^(-9) M`
`2.2 xx 10^(-4) M`

Solution :`{:(,CaCl_(2),hArr,Ca^(2+)+,2Cl^(-)),("Concen.",0.04,,0.04,0.08):}`
For AgCl
`AgCl hArr AG^(+) + Cl^(-)`
`K_(sp) = [Ag^(+)][Cl^(-)]`
`4.0 xx 10^(-10) = [S][S+0.08]`
`4.0 xx 10^(-10) = S^(2) + S xx 0.08 [S^(2) lt lt lt 1]`
`4.0 xx 10^(-10) = S xx 0.08`
`S = (4.0 xx 10^(-10))/(0.08) = 0.5 xx 10^(-8) = 5 xx 10^(-9)`.


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