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The solubility prouduct of `AgCI is 1.5625xx10^(-10)` at ` 25^(@)`C its solubility in grams per litre will be :-A. 143 .5B. 108C. `1.57xx10^(-8)`D. `1.79xx10^(-3)` |
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Answer» Correct Answer - D `S=(mol)/(Litre)` Now in `grm //litre = 5xxm.wt` `Ksp=1.56 25xx10^(-10)` ` s=1.25xx10^(-5)mol//L` `s=143.5xx1.25xx10^(-5)gm//L` |
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