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The solubility product of AgCl is 2.0 X 10-10 mol2 dm-6. The maximum concentration of Ag+ ions in the solution is ? |
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Answer» 1.414 X 10-5 MOL dm-3Explanation:solubility product for AgCl = [Ag+]×[Cl-]2.0×10^(-10) mol² dm^(-6) = [Ag+] × [Cl-][Ag+] = 2.0×10^(-10) ÷ [Cl-] mol dm^(-3)here, concentration of Cl ION , i.e., [Cl-] , is that GIVEN in solutions ( whose value has not been given here)put the value of [Cl-] , u will get your answerAnd correct answer is 1.414 x 10-5 mol dm-3 |
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