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The Solubility product of A2B is 32×10^-9.Calculate its solubility |
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Answer» The equation for the reaction will be as follows: A2B ⇌ 2A++B- By Stoichiometry, 1 mole of A2B gives 2 moles of and 1 mole of B Thus if solubility of A2B is s moles/liter, solubility of A is 2s moles\liter and solubility of B is s moles/liter Therefore, Ksp = [2A+]2[B-] Ksp = [2s]2[s] 4s3 = 32 x 10-9 mol3L-1 s = 2 x 10-3 moles/liter Hence, the solubility of A2B is 2 x 10-3 moles/liter |
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