1.

The Solubility product of A2B is 32×10^-9.Calculate its solubility

Answer»

The equation for the reaction will be as follows:

A2B  ⇌ 2A++B-

By Stoichiometry,

1 mole of A2B  gives 2 moles of  and 1 mole of B

Thus if solubility of  A2B is s moles/liter, solubility of A is 2s moles\liter and solubility of B is s moles/liter

Therefore,

Ksp = [2A+]2[B-]

Ksp = [2s]2[s]

4s3 = 32 x 10-9 mol3L-1

s = 2 x 10-3 moles/liter

Hence, the solubility of A2B is 2 x 10-3 moles/liter



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