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The solubility product of a sparingly soluble metal hydroxide `M (OH)_(2)` at 298 K is `5xx10^(-16) "mol"^(3) "dm"^(-9)`. The pH value of its queous and saturated solution isA. 5B. 9C. `11.5`D. `2.5` |
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Answer» Correct Answer - B `{:(M(OH)_(2),hArr,M^(2+),+,2OH^(-)),(,,s,,2s):}` `K_(sp)=(s) (2s)^(2)=4s^(3)` `s^(3)=(K_(sp))/(4)=(5xx10^(-16))/(4)=1.25xx10^(-16)` `=125xx10^(-18)` `:. S=5xx10^(-6)M, i.e., [OH^(-)]2xx5xx10^(-6)M` `=10^(-5)M` pOH = 5.0 pH=14-5 = 9 |
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