1.

The solubility of AgCl (Ksp = 1.2 x 10–10) in a 0.10 M NaCl solution is:(a) 0.1 M (b) 1.2 x 10–6 M(c) 1.2 x 10–9 M (d) 1.2 x 10–10 M

Answer»

Correct option: (c) 1.2 x 10–9 M

Explanation: 

Ksp AgCl = 1.2 x 10–10 = [Ag+] [Cl] = [s][s + 0.1]

where s is solubility of AgCl

∴ Ksp = s x 0.1 = 1.2 x 10–10

∴ s = 1.2 x 10–9 M



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