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The solubility of AgCl (Ksp = 1.2 x 10–10) in a 0.10 M NaCl solution is:(a) 0.1 M (b) 1.2 x 10–6 M(c) 1.2 x 10–9 M (d) 1.2 x 10–10 M |
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Answer» Correct option: (c) 1.2 x 10–9 M Explanation: Ksp AgCl = 1.2 x 10–10 = [Ag+] [Cl–] = [s][s + 0.1] where s is solubility of AgCl ∴ Ksp = s x 0.1 = 1.2 x 10–10 ∴ s = 1.2 x 10–9 M |
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