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The solubility of AgCl is m g dm^-3.If 1 mole of AgCl weighs M g the solubility product of AgCl will be A) m^2/M B) m/M^2 C) m^2/M^2 D) m^2M^2 |
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Answer» Iᴛ sᴇᴇᴍᴇᴅ ᴛʜᴀᴛ ʙʀᴀɪɴʟʏ ᴍᴏᴅᴇʀᴀᴛᴏʀs ᴅᴏᴇsɴᴏᴛ ʟɪᴋᴇ ᴍʏ ᴀɴsᴡᴇʀ sᴏ ᴛʜᴀᴛ ɪ ʜᴀᴅ ᴛᴏ ᴛᴀᴋᴇ sᴄʀᴇᴇɴsʜᴏᴛ ᴏғ ɪᴛ |
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