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The simple interest on a principal for 2 years at 10% p.a. is Rs. 1700. Find the principal amount.chapter : compound interest 9thpls help fast​

Answer»

DIRECT Answer:

Rs.8500

Given:

Rate of Interest [R] = 10% p.a.

Time period [T] = 2 years

Simple Interest [SI] = Rs.1700

To FIND:

The principal amount [P].

Solution:

Here, we have to implement the concept of simple interest to find the principal amount on which the given simple interest is levied. The formula to be used is:

\tt{\implies\:Simple\:Interest=\dfrac{P\times\:R\times\:T}{100}}

Here, we know the values of R, T and SI. Implementing these values into the equation,

\sf{\longrightarrow\:1700=\dfrac{P\times10\times2}{100}}

\sf{\longrightarrow\:1700=\dfrac{P\times1\times2}{10}}

\sf{\longrightarrow\:1700=\dfrac{P}{5}}

\sf{\longrightarrow\:P=1700\times5}

\sf{\longrightarrow\:P=8500}

Therefore the principal amount is Rs.8500.

Verification:

If we substitute the value of P into the LHS of the equation and obtain the simple interest as provided in the QUESTION, our answer is correct.

LHS:

\sf{\implies\:\dfrac{P\times\:R\times\:T}{100}}

\sf{\longrightarrow\:\dfrac{8500\times10\times2}{100}}

\sf{\longrightarrow\:85\times20}

\sf{\longrightarrow\:1700}

RHS:

\sf{\implies\:1700}

LHS = RHS

Hence verified!



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