1.

The sides of a rectangle are in the ratio 3 : 7 and its area is 1029 m². Find the dimensions of the rectangle, and then find its perimeter.

Answer»

\mathfrak{\large{\underline{\underline{Answer :-}}}}

The Perimeter of the Rectangle is 140 m.

\mathfrak{\large{\underline{\underline{Explanation :-}}}}

GIVEN :

Ratio of the Rectangle sides = 3 : 7

Area of the Rectangle = 1029 m²

To Find :

The dimensions and Perimeter of the Rectangle

Solution :

Consider the Breadth as 3X

Consider the Length as 7x

\purple{\boxed{\sf{\pink{Area = Length \times Breadth}}}}

\tt{\implies} \: 1029 = 7x \times 3x

\tt{\implies} \: 21x^{2} = 1029

\tt{\implies} \: x =  \dfrac{1029}{21}

\tt{\implies} \: x = \sqrt{49}

\tt{\implies} \: x = 7

\rule{300}{1.5}

Value of 3x

\tt{\implies} \: 7 \times 3

\tt{\implies} \: 21

Value of 7x

\tt{\implies} \: 7 \times 7

\tt{\implies} \: 49

Breadth = 21 m

Length = 49 m

\rule{300}{1.5}

Perimeter of Rectangle can be FOUND as the dimensions are given.

\purple{\boxed{\sf{\pink{Perimeter = 2(Breadth+Length)}}}}

\tt{\implies} \: 2(21 + 49)

\tt{\implies} \: 42+ 98

\tt{\implies} \:140

\therefore The Perimeter of the Rectangle is 140 m.



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