1.

The sides AB and CD of a cyclicquadrilateral ABCD are producedto meet at P. The sides AD and BCare produced to meet at Q. If<ADC = 85° and <BPC = 40°, then<BAD is equal to

Answer»

in triangle 🔺 ADP, A+D+P=180THUS, A=180-(85+40) A=180-125 A=55



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