the side of a triangle are in the ratio 2:3:4 if the perimeter of the

1.	the side of a triangle are in the ratio 2:3:4 if the perimeter of the triangle is 120 cm find the side . what know of the triangle is?
Answer» ${\huge{\underline{\underline{\rm{Question:}}}}}$ ★ The sides of a triangle are in the ratio 2:3:4 . If the perimeter of the triangle is 120 cm , FIND the sides of the triangle . ${\huge{\underline{\underline{\rm{Answer\checkmark}}}}}$ ★ GIVEN : The ratio of sides = 2:3:4 Perimeter = 120 cm ★ To Find : The sides of the triangle . ★ SOLUTION : Let the ratios be 2x , 3x and 4x That is , 1st side = 2x 2nd side = 3x 3rd side = 4x As we know , $\star \boxed{ \sf \: perimeter_{triangle} = 120 \: cm}$ Here , $\rm \mapsto \: 1st \: side + 2nd \: side + 3rd \: side = 120cm$ $\mapsto \rm \: 2x + 3x + 4x = 120 \: cm$ $\mapsto \rm \: \cancel{9}x = \cancel{120} \: cm$ $\mapsto \rm \: 3x = 40 \: cm$ $\mapsto \boxed{\rm x = \dfrac{40}{3} \: cm}$ So , Sides are : $\sf \: 1st \: side \: = 2x = 2 \times \dfrac{40}{3} = \boxed{ \sf\dfrac{80}{3} \: cm}$ $\sf \: 2nd \: side = 3x = 3 \times \dfrac{40}{3} = \boxed{ \dfrac{120}{3} \sf\: cm}$ $\sf \: 3rd \: side = 4x =4 \times \frac{40}{3} = \boxed{ \sf \frac{160}{3} \: cm} \\$ Since all the sides are DIFFERENT in LENGTH , So, It's a Scalene Triangle .

the side of a triangle are in the ratio 2:3:4 if the perimeter of the triangle is 120 cm find the side . what know of the triangle is?

Answer»

${\huge{\underline{\underline{\rm{Question:}}}}}$

★ The sides of a triangle are in the ratio 2:3:4 . If the perimeter of the triangle is 120 cm , FIND the sides of the triangle .

${\huge{\underline{\underline{\rm{Answer\checkmark}}}}}$

Let the ratios be 2x , 3x and 4x

That is ,

As we know ,

$\star \boxed{ \sf \: perimeter_{triangle} = 120 \: cm}$

Here ,

$\rm \mapsto \: 1st \: side + 2nd \: side + 3rd \: side = 120cm$

$\mapsto \rm \: 2x + 3x + 4x = 120 \: cm$

$\mapsto \rm \: \cancel{9}x = \cancel{120} \: cm$

$\mapsto \rm \: 3x = 40 \: cm$

$\mapsto \boxed{\rm x = \dfrac{40}{3} \: cm}$

So , Sides are :

$\sf \: 1st \: side \: = 2x = 2 \times \dfrac{40}{3} = \boxed{ \sf\dfrac{80}{3} \: cm}$
$\sf \: 2nd \: side = 3x = 3 \times \dfrac{40}{3} = \boxed{ \dfrac{120}{3} \sf\: cm}$
$\sf \: 3rd \: side = 4x =4 \times \frac{40}{3} = \boxed{ \sf \frac{160}{3} \: cm} \\$

Since all the sides are DIFFERENT in LENGTH ,

So,

It's a Scalene Triangle .