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The shortest distance from the plane 12x + 4y + 3z = 327 to the sphere x2+y2+z2+4x−2y−6z=155 is |
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Answer» The shortest distance from the plane 12x + 4y + 3z = 327 to the sphere x2+y2+z2+4x−2y−6z=155 is |
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