1.

The shortest distance between the skew lines →r=→r1+t→a1 and →r=→r2+n−→a2, where →r1=9j+2k, →a1=3i−j+k, →r2=−6i−5j+10k, →a2=−3i+2j+4k is 3√a. Then the value of a is:

Answer» The shortest distance between the skew lines r=r1+ta1 and r=r2+na2, where r1=9j+2k, a1=3ij+k, r2=6i5j+10k, a2=3i+2j+4k is 3a. Then the value of a is:


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