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The short-wavelength limit shifts by 26 pm when the operating voltage in an X-ray tube is increased to 1.5 times the original value. What was the original value of the operating voltage? |
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Answer» Correct Answer - A `26 pm = 0.26 Å` Now, 0.26 = (12475)/(V) - (12375)/(1.5 V). |
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