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The short and long hands of a clock are 4 cm and 6 cm long respectively. Find the sum of distances travelled by their tips in 2 days. [take pi = 3.14] |
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Answer» The short and long hands of a clock are 4 cm and 6 cm long respectively. In an hour the hour hand completes one rotation in 12 hours therefore in 24 hours it will complete 2 rotations. Similarly, the minute hand completes one rotation therefore in 24 hours the minute hand will complete 24 rotations. Distance travelled by its tip in 2 days = 4(circumference of the circle with radius 4 cm) = (4 × 2π × 4) cm = 32π cm (As, in 2 days, the short hand will complete 4 rounds) In 2 days, the long hand will complete 48 rounds length moved by its tip = 48(circumference of the circle with radius 6 cm) = (48 x 2π x 6) cm = 576 π cm Now, Sum of the lengths moved = (32π + 576π) = 608π cm = (608 x 3.14) cm = 1909.12 cm |
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