1.

The sealed containers of the same capacity and at the same temperature are filled with 44 g of H_(2) in one and 44 g of CO_(2) in the other. If the pressre of carbon dioxide in the second container is 1 atm. That of hydrogen in the first container would be.

Answer»

<P>1 ATM
10 atm
22 atm
44 atm

Solution :`(P_(1)V_(1))/(P_(2)V_(2))=(n_(1)RT_(1))/(n_(2)RT_(2))=(n_(1)T_(1))/(n_(2)T_(2))`
As, `V_(1) =V_(2) & T_(1) =T_(2)`
`(P_(1))/(P_(2))=(n_(1))/(n_(2))`
`(P_(H_(2)))/(P_(co_(2)))=(n_(H_(2)))/(n_(co_(2)))`
`(P_(H_(2)))/(1)=(44//2)/(44//44)=22` atm
Hence, (C ) is the correct answer.


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