The scalar product of two vectors, Ā=2î +5kand B = 39 +4Â is

1.	The scalar product of two vectors, Ā=2î +5kand B = 39 +4Â is
Answer» Answer: scelar product means dot product of two VECTORS ( A and B) is A . B = ( 2i + 5K) . ( 3J + 4K) = ( 2i + 0j + 5k) . ( 0i +3j + 4k) = ( 2 * 0) + ( 0 3) + (5 4) ( because i. i =1; j. j =1 ; k. k =1; i. j =0; j. K =0; k. i =0) = 0 +0+ 20 = 20 (answer).

Answer»

Answer:

scelar product means dot product of two VECTORS ( A and B) is

A . B = ( 2i + 5K) . ( 3J + 4K)

= ( 2i + 0j + 5k) . ( 0i +3j + 4k)

= ( 2 * 0) + ( 0 *3) + (5 * 4)

( because i. i =1; j. j =1 ; k. k =1; i. j =0; j. K =0; k. i =0)

= 0 +0+ 20

= 20 (answer).

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The scalar product of two vectors, Ā=2î +5kand B = 39 +4Â is​

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The scalar product of two vectors, Ā=2î +5kand B = 39 +4Â is