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The roots of the quadratic equation 3(x+3)^2 = 48 are _______. |
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Answer» Answer: x₁ = -7 x₂ = 1 Step-by-step explanation: 3(x+3)² = 48 3(x² + 6x + 9) = 48 x² + 6x + 9 = 48 / 3 x² + 6x + 9 = 16 x² + 6x + 9 - 16 = 0 x² + 6x - 7 = 0 (x + 7)(x - 1) = 0 x + 7 = 0 x₁ = -7 x - 1 = 0 x₂ = 1 |
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