1.

The roots of the quadratic equation 3(x+3)^2 = 48 are _______.

Answer»

Answer:

x₁ = -7

x₂ = 1

Step-by-step explanation:

3(x+3)² = 48

3(x² + 6x + 9) = 48

x² + 6x + 9 = 48 / 3

x² + 6x + 9 = 16

x² + 6x + 9 - 16 = 0

x² + 6x - 7 = 0

(x + 7)(x - 1) = 0

x + 7 = 0

x₁ = -7

x - 1 = 0

x₂ = 1



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