1.

The roots of the equation 6x^2+bx+c = 0 are "alpha" and "1/alpha", then the value of 'c' in this equation is? Pls help dont spam

Answer»

Step-by-step EXPLANATION:

SUM of zeroes = 1/alpha + alpha

= 1+ alpha ²/ alpha

-b/C

So c is alpha ..



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