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The resultant of `vec(A)+vec(B) is vec(R )_(1)`. On reversing the vector `vec(B)`, the resultant becomes `vec(R )_(2)`. What is the value of `R_(1)^(2)+R_(2)^(2)`?A. `A^(2)+B^(2)`B. `A^(2)-B^(2)`C. `2(A^(2)+B^(2))`D. `2(A^(2)-B^(2))` |
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Answer» Correct Answer - C `R_(1)^(2)=A^(2)+B^(2)+2AB cos theta` `|vecR_(2)|=|vecA-vecB|rArrR_(2)^(2)=A^(2)+B^(2)-2AB cos theta` thus `R_(1)^(2)+R_(2)^(2)=2(A^(2)+B^(2))` |
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