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The resolution of an encoder with 10 tracks will be nearly (a) 0.15° (b) 0.25° (c) 0.35° (d) 0.45° |
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Answer» Correct option is (c) 0.35° If the encoder has ‘N’ tracks then the resolution = \(\cfrac{360°}{2^N}\) In the given data N = 10 So, Resolution = \(\cfrac{360°}{2^{10}}\) = 0.35° |
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