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The resistsnce of a wire is 10 ohm its length is increased by 10% by stretching . The new resistance will now be |
| Answer» EXPLANATION:Handy trickIf the QUESTION doesn't gives clue about CHANGE in volume.The NEW resistance = { 1+(x/100)}^2 of Initial resistance , where x= the increment percent.Here in ur ques , x= 10% and R= 10 ohmTherefore, the new resistance ={1+(10/100)}^2 ×10= { 110/100}^2 × 10= 12.1 ohm | |