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The resistances corresponding to the lower and the uppper fixed points, in a platinum resistance thermometer are 3.50Omegaand3.65Omega. What would be the resistance at a temperature equal to the freezing point of mercury (-37^(@)C)? |
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Answer» Solution :Given `R_(0) =3.50 Omega , R_(100) = 3.65 Omega and t = - 37^@C , R_(t) = ? ` `:.` Using `t=[(R_t-R_0)/(R_(100)-R_0)]100^@C` We have , `-37^@C=[(R_(t)-3.50)/(3.65-3.50)]100^@CimpliesR_(t)-3.50=-0.056impliesR_(t)=3.55Omega` `:.` The REQUIRED RESISTANCE is `3.55 Omega` . |
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