The resistances corresponding to the lower and the upper fixed points, in a platinum resistance thermometer are 3.59 Omega and 3.65 Omega. What would be the resistance at a temperature equal to the freezing point of mercury(-37^(@)C)?

The resistances corresponding to the lower and the upper fixed points,

1.	The resistances corresponding to the lower and the upper fixed points, in a platinum resistance thermometer are 3.59 Omega and 3.65 Omega. What would be the resistance at a temperature equal to the freezing point of mercury(-37^(@)C)?
Answer» Solution :Given : `R_(0) = 3.50 OMEGA, R_(100) = 3.65 Omega` and t = `-37^(@)C, R_(t) ` = ? Using t = `[ (R_(t) - R_(0))/(R_(100) - R_(0)) ] 100^(@)C ` We have , - `37^(@)C = [ (R_(t) - 3.50)/(3.65 - 3.50) ] 100^(@)` C `RARR R_(t) - 3.50 = - 0.056 "" R_(t) = 3.55 Omega` . `THEREFORE ` The required RESISTANCE is `3.55 Omega`