1.

The resistance of conductivity cell containing 0.001M KCl solution at 298K is 1500Ω. What is the cell constant if the conductivity of 0.001M KCl solution at 298K is 0.146 x 10-3 S cm-1. 

Answer»

Cell constant = Conductivity x Resistance

 = 0.146 x 10-3 S cm-1 x 1500 = 0.219 cm-1 



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