1.

The resistance of a carbon resistor with four coloured rings is \( (500 \pm 50) \Omega \). Identify the colour of fourth ring.

Answer»

Given resistance R = \((500\pm50)\Omega\)

We can write 

R = (50 x 101± 10%)

it means

First ring 5 - Green color

Second ring 0 - Black

Third ring 101 = Brown

Fourth 10% = Silver

its mean colour of fourth ring will be silver.



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