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The repulsive force between two magnetic poles in air is 9 xx 10^(-3) N. if the two poles are equal in strength and are separated by a distance of 10 cm , calculate the pole strength of each pole . |
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Answer» Solution :The FORCE between TWO poles are given by `vecF= k (q_(m_(A)) q_(m_(D)))/(r^(2))` The magnitude of the force is `F=k (q_(m_(A)) q_(m_(B)))/(r^(2))` Given: `F=9 xx 10^(-3) N, r=10 cm =10 xx 10^(-2) m` Therefore, `9 xx 10^(-3) =10^(-7) xx (q_(m)^(2))/((10 xx 10^(-2))^(2)) rArr q_(m)=30NT^(-1)` |
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