1.

The remainder when the square of any prime number greater than 3 is divided by 6, is(a) 1(b) 3(c) 2(d) 4[Hint: Any prime number greater than 3 is of the from 6k ± 1, where k is a natural number and (6k ± 1)2 = 36k2 ± 12k + 1 = 6k(6k ± 2) + 1]

Answer» The remainder when the square of any prime number greater than 3 is divided by 6, is



(a) 1

(b) 3

(c) 2

(d) 4



[Hint: Any prime number greater than 3 is of the from 6k ± 1, where k is a natural number and (6k ± 1)2 = 36k2 ± 12k + 1 = 6k(6k ± 2) + 1]


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