Saved Bookmarks
| 1. |
The remainder when the square of any prime number greater than 3 is divided by 6, is(a) 1(b) 3(c) 2(d) 4[Hint: Any prime number greater than 3 is of the from 6k ± 1, where k is a natural number and (6k ± 1)2 = 36k2 ± 12k + 1 = 6k(6k ± 2) + 1] |
|
Answer» The remainder when the square of any prime number greater than 3 is divided by 6, is (a) 1 (b) 3 (c) 2 (d) 4 [Hint: Any prime number greater than 3 is of the from 6k ± 1, where k is a natural number and (6k ± 1)2 = 36k2 ± 12k + 1 = 6k(6k ± 2) + 1] |
|