1.

The relation In x + ln(1 + x) = 0 means:x2 + x - 1 = 0x2 +2+1 = 0x2 +x-e=0x2 + x+ e = 0​

Answer»

ln x + ln (1+x) = 0

=> ln {x(1+x)} = 0

=> ln (x+x²) = ln (1)

=> x²+x = 1

=> x²+x-1 = 0 ------- (1) .

Hope it's HELPFUL to you .


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