1.

The reduction potential ofhydrogen half-cell will be negative if:

Answer»

`p(H_(2))=1` ATM and `[H^(+)]=2.0M`
`p(H_(2)) =1` atmand `[H^(+)] =1.01M`
`p (H_(2)) =2` atm and `[H^(2)]=1.0M`
`p(H_(3))=2` atm and `[H^(+)]=2.0M`

Solution :`H^(+) +e ^(-) to 1/2 H_(2)`
`E =E^(@) =(0.059)/(1) log ""([P (H_(2))]^(1//2))/([H^(+)])`
Now if`PH_(2)=2`atm and `[H^(+)]=LM`
then `E= 0- (0.059)/(1) log""(2^(1//2))/(1) =(-0.059)/(2) log 2`


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