The reduction of peroxydisulphate ion by I– ion is expressed by S2O2 – InterviewSolution

1.	The reduction of peroxydisulphate ion by I– ion is expressed by S2O2−8+3I−→2SO2−4+I−3If the rate of disappearance of I– is 9/2×10–3 mol/L−1 s−1, what is the rate of formation of SO2−4 during the same time?
Answer» The reduction of peroxydisulphate ion by $I^{-}$ ion is expressed by $S_{2} O_{8}^{2 -} + 3 I^{-} \to 2 S O_{4}^{2 -} + I_{3}^{-}$ If the rate of disappearance of $I^{-}$ is $9 / 2 \times 10^{- 3} {mol/L}^{- 1} s^{- 1}$ , what is the rate of formation of $S O_{4}^{2 -}$ during the same time?

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