The recoil speed of a free H-atom at rest in fourth excited state, when it undergoes a transition to ground state is (mass of the H atom = 1.67×10−27 kg and assume exciting energy is taken by the atom)(write upto two decimal places) in m/s is [Take h=6.68×10−34 Js and RH=1×107 m−1]

The recoil speed of a free H-atom at rest in fourth excited state, whe

1.	The recoil speed of a free H-atom at rest in fourth excited state, when it undergoes a transition to ground state is (mass of the H atom = 1.67×10−27 kg and assume exciting energy is taken by the atom)(write upto two decimal places) in m/s is [Take h=6.68×10−34 Js and RH=1×107 m−1]
Answer» The recoil speed of a free H-atom at rest in fourth excited state, when it undergoes a transition to ground state is (mass of the H atom = $1.67 \times 10^{- 27}$ kg and assume exciting energy is taken by the atom)(write upto two decimal places) in $m / s$ is [Take $h = 6.68 \times 10^{- 34} J s$ and $R_{H} = 1 \times 10^{7} m^{- 1}$ ]

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The recoil speed of a free H-atom at rest in fourth excited state, when it undergoes a transition to ground state is (mass of the H atom = 1.67×10−27 kg and assume exciting energy is taken by the atom)(write upto two decimal places) in m/s is [Take h=6.68×10−34 Js and RH=1×107 m−1]

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