The reaction of heated graphite with superheated steam is endothermic; C (graphite)+H2 O(g)→CO g)+H2 (g) 1 The heat required for this reaction is provided by burning part of the graphite; C (graphite)+O2 (g)→CO2 (g);△H∘(500K)=−393.7 kJmol−1 2. If 1.34 mole of graphite is required for production of 1 mole of Hydrogen at 500 K. What is △H∘(500K) for reaction (1) ?

The reaction of heated graphite with superheated steam is endothermic;

1.	The reaction of heated graphite with superheated steam is endothermic; C (graphite)+H2 O(g)→CO g)+H2 (g) 1 The heat required for this reaction is provided by burning part of the graphite; C (graphite)+O2 (g)→CO2 (g);△H∘(500K)=−393.7 kJmol−1 2. If 1.34 mole of graphite is required for production of 1 mole of Hydrogen at 500 K. What is △H∘(500K) for reaction (1) ?
Answer» The reaction of heated graphite with superheated steam is endothermic; $C (g r a p h i t e) + H_{2} O (g) \to C O g) + H_{2} (g) 1$ The heat required for this reaction is provided by burning part of the graphite; $C (g r a p h i t e) + O_{2} (g) \to C O_{2} (g); △ H^{\circ} (500 K) = - 393.7 k J m o l^{- 1} 2$ . If 1.34 mole of graphite is required for production of 1 mole of Hydrogen at 500 K. What is $△ H^{\circ} (500 K)$ for reaction (1) ?