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The reaction 2o3----> 3o2 proceeds as followso3 o2+o (fast)o+o3 2o2 (slow)the rate law expression for the reaction would be 1) r=k[o3]^22) r= k[o3]^2 [o2]^-13) r= k[o3] [o2]4) r= [o2]^1 |
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Answer» The reaction 2o3----> 3o2 proceeds as follows o3 <====>o2+o (fast) o+o3 <====>2o2 (slow) the rate law expression for the reaction would be 1) r=k[o3]^2 2) r= k[o3]^2 [o2]^-1 3) r= k[o3] [o2] 4) r= [o2]^1 |
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