Saved Bookmarks
| 1. |
The ray of light is incident at an angle 60°on one face of a rectangular slab of thickness 0.1m and refractive index 1.5. calculate the lateral shift produced |
|
Answer» Lateral shift formula is L = t*sin(i-r)/cos(r) t = 0.1m i = 60° As we don't KNOW 'r'. We can find out usinf SNELLS law n1sin(i) = n2sin(r) 1*sin60° = 1.5*(sinr) 1/√3 = sin(r) USING identity cos(r) = √(2/3) tan(r) = 1/√2 sin(i-r) = sin(i)cos(r) - sin(r)cos(i) sin(i-r)/cos(r) = sin(i) - tan(r)cos(i) = (√3/2) - (1/√2)(1/2) = (√6 - 1)/2√2 = 0.51 L = 0.1*0.51 = 0.051m = 5.1cm |
|