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The ratio of the speeds of a train and a man is 6:1. The length of the train is 650 mand crosses a pole in 1 minute 5 seconds. In how much time will the man cross the240m long platform? |
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Answer» Answer: 2.5 mins or 2 min 30s Step-by-step explanation: Ratio of velocity of train and man = 6:1 Length of train(L) = 650m Length of platform(L’) = 240m time taken by train to cross a pole (which we are CONSIDERING to be of negligible length ) = 1 min 5 SEC or 65 s In other words, the train travels its length in 65s [As, by the formula v=(L+L’/t) here L’ = 0; so v = L/t] speed of train = 650/65 = 10m/s Now man’s speed is simply 1/6 of train velocity, as indicated by the ratio, so speed of man = 10/6 = 1.6m/s So, time taken by the man to cross 240 m platform at CONSTANT speed then time is 240/1.6 m/s = 150 s = 2.5 mins or 2 min 30 s |
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