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The ratio of the speed of the electron in the first Bohr orbit of hydrogen and the speed of light is equal to (where `e, h and c` have their usual meaning in cgs system)A. `2 pi h // e^(2)`B. `e r^(2) h// 2 pi c`C. `e ^(2) c// 2 pi h`D. `2 pi e^(2)// h c` |
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Answer» Correct Answer - D `v_(n) = k (2 pi e^(2))/(n h)` We know that in cgs system`k = 1` `:. v_(n) = (2 pi e^(2))/(n h) implies v_(1) = (2 pi e^(2))/(h)` So `(v_(1))/(c) = k (2 pi e^(2))/(c h)` |
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