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The ratio of the speed of a projectile at the point of projection to the speed at the top of its trajectory is x. The angle of projection with the horizontal isA. `sin^(1) x`B. `cos^(-1)x`C. `sin^(-1) (1//x)`D. `cos^(-1) (1//x)` |
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Answer» Correct Answer - D Speed of projectile at the point of projection = u Speed of projectile at the top of its trajectory `= u cos theta`. `(u)/(u cos theta) = x` or `cos theta = (1)/(x) rArr theta = cos^(-1)((1)/(x))` |
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