The ratio of the quantities of acid and water in a mixture is 1 : 3. I

1.	The ratio of the quantities of acid and water in a mixture is 1 : 3. If 5 L of acid is further added to the mixture, then the new ratio becomes 1 : 2. The quantity of new mixture in litres is.1. 322. 453. 424. 405. 35
Answer» Correct Answer - Option 2 : 45 Given: The ratio of the quantities of acid and water in a mixture is 1 : 3 After added 5 L of acid, the new ratio becomes 1 : 2 Concept Used: New quantity of Acid/New quantity of Water = (Quantity of Acid + Quantity of Added Acid)/(Quantity of Water + Quantity of Added Water) Calculation: Let the quantity of acid in the original mixture be x litres. And, that of water be 3x L New quantity of Acid/New quantity of Water = (Quantity of Acid + Quantity of Added Acid)/(Quantity of Water + Quantity of Added Water) ⇒ (x + 5)/3x = 1/2 ⇒ 2x + 10 = 3x ⇒ x = 10 Quantity of new mixture = 4x + 5 ⇒ 4 × 10 + 5 = 45 litres ∴ The quantity of new mixture in liters is 45 litres.

The ratio of the quantities of acid and water in a mixture is 1 : 3. If 5 L of acid is further added to the mixture, then the new ratio becomes 1 : 2. The quantity of new mixture in litres is.1. 322. 453. 424. 405. 35

Answer» Correct Answer - Option 2 : 45

Given:

The ratio of the quantities of acid and water in a mixture is 1 : 3

After added 5 L of acid, the new ratio becomes 1 : 2

Concept Used:

New quantity of Acid/New quantity of Water = (Quantity of Acid + Quantity of Added Acid)/(Quantity of Water + Quantity of Added Water)

Calculation:

Let the quantity of acid in the original mixture be x litres.

And, that of water be 3x L

New quantity of Acid/New quantity of Water = (Quantity of Acid + Quantity of Added Acid)/(Quantity of Water + Quantity of Added Water)

⇒ (x + 5)/3x = 1/2

⇒ 2x + 10 = 3x

⇒ x = 10

Quantity of new mixture = 4x + 5

⇒ 4 × 10 + 5 = 45 litres

∴ The quantity of new mixture in liters is 45 litres.

Discussion

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