1.

The ratio of the longest to shortest wavelength in Brackett series of hydrogen spectra isA. `(25)/(9)`B. `(17)/(6)`C. `(9)/(5)`D. `(4)/(3)`

Answer» Correct Answer - A
For Bracket series `(1)/(lambda_(max)) = R[(1)/(4^(2)) - (1)/(5^(2))] = (9)/(25 xx 16) R`
and `(1)/(lambda_(min)) = R[(1)/(4^(2)) - (1)/(oo^(2))] = (R )/(16) rArr (lambda_(max))/(lambda_(min)) = (25)/(9)`


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