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The ratio of the largest to shortest wavelength in Lyman series of hydrogen spectra isA. `(25)/(9)`B. `(17)/(6)`C. `(9)/(5)`D. `(4)/(3)` |
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Answer» Correct Answer - D For Lyman series `(1)/(lambda_(max)) = R [(1)/(1^(2)) - (1)/(2^(2))] = (3)/(4)R` and `(1)/(lambda_(min)) = R[(1)/(1^(2)) - (1)/(oo^(2))] = (R )/(1) rArr (lambda_(max))/(lambda_(min)) = (4)/(3)` |
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