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The ratio of the difference in energy between first and second Bohr orbit to that between second and third Bohr orbit in H-atom is :-(1) 4/9(2) 1/3(3) 27/5(4) 1/2 |
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Answer» (2) 1/3 is the RIGHT answerExplanation:LET E¹ be energy ASSOCIATED from FIRST ORBIT to second.Therefore, E¹ = -Rydberg's constant*(1/1 - 1/2)= = -Rydberg's constant*(1/2). --- (i)Let E² be energy associated from second to third orbit.Therefore, E² = -Rydberg's constant*(1/2 - 1/3)= -Rydberg's constant*(1/6) --- (ii)Divide (ii) and (i) :-We get 1/3 |
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