Saved Bookmarks
| 1. |
The ratio of the areas of two squares one having its diagonal double that of the other is |
|
Answer» Answer: 1:4 Step-by-step EXPLANATION: Diagonal of square of SIDE S is √2×S Let the length of the SMALL diagonal be X then, the length of the larger diagonal is 2X Let the length of the side of the small square be Q √2×Q=X Q=X÷√2 =(√2×X)/2 Area of square of side Q=Q²=X²÷4 Let the length of the side of the BIG square be W W×√2=2X W=2X÷√2 =√2×X Area of square of side W=W²=1÷2X² Q²:W²=1:4 |
|