1.

The ratio of the areas of two squares one having its diagonal double that of the other is ​

Answer»

Answer:

1:4

Step-by-step EXPLANATION:

Diagonal of square of SIDE S is √2×S

Let the length of the SMALL diagonal be X

then, the length of the larger diagonal is 2X

Let the length of the side of the small square be Q

√2×Q=X

Q=X÷√2

=(√2×X)/2

Area of square of side Q=Q²=X²÷4

Let the length of the side of the BIG square be W

W×√2=2X

W=2X÷√2

=√2×X

Area of square of side W=W²=1÷2X²

Q²:W²=1:4



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