1.

The ratio of the ages of a man and his wife is 4:3.After 4 years, this ratio will be 9: 7. If at the timeof marriage, the ratio was 5:3, then how manyyears ago were they married?ESTATE

Answer»

Let the present age of the man and his wife be4xand3xrespectively.

After4years this ratio will become9:7⇒(4x+4):(3x+4)=9:7⇒7(4x+4)=9(3x+4)⇒28x+28=27x+36⇒x=8

Present age of the man=4x=4×8=32Present age of his wife=3x=3×8=24

Assume that they got married beforet years. Then,(32−t):(24−t)=5:3⇒3(32−t)=5(24−t)⇒96−3t=120−5t⇒2t=24

t=24/2=12 years



Discussion

No Comment Found